254940133 has 4 divisors (see below), whose sum is σ = 291360160. Its totient is φ = 218520108.

The previous prime is 254940113. The next prime is 254940137. The reversal of 254940133 is 331049452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-254940133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 254940095 and 254940104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (254940137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18210003 + ... + 18210016.

It is an arithmetic number, because the mean of its divisors is an integer number (72840040).

Almost surely, 2^254940133 is an apocalyptic number.

It is an amenable number.

254940133 is a deficient number, since it is larger than the sum of its proper divisors (36420027).

254940133 is an equidigital number, since it uses as much as digits as its factorization.

254940133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36420026.

The product of its (nonzero) digits is 12960, while the sum is 31.

The square root of 254940133 is about 15966.8448041559. The cubic root of 254940133 is about 634.0829410144.

Adding to 254940133 its reverse (331049452), we get a palindrome (585989585).

The spelling of 254940133 in words is "two hundred fifty-four million, nine hundred forty thousand, one hundred thirty-three".