255001110113 has 2 divisors, whose sum is σ = 255001110114. Its totient is φ = 255001110112.

The previous prime is 255001110097. The next prime is 255001110131. The reversal of 255001110113 is 311011100552.

It is a happy number.

Together with next prime (255001110131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206145965089 + 48855145024 = 454033^2 + 221032^2 .

It is a cyclic number.

It is not a de Polignac number, because 255001110113 - 2⁴ = 255001110097 is a prime.

It is not a weakly prime, because it can be changed into another prime (255001110313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127500555056 + 127500555057.

It is an arithmetic number, because the mean of its divisors is an integer number (127500555057).

Almost surely, 2^255001110113 is an apocalyptic number.

It is an amenable number.

255001110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

255001110113 is an equidigital number, since it uses as much as digits as its factorization.

255001110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 20.

Adding to 255001110113 its reverse (311011100552), we get a palindrome (566012210665).

The spelling of 255001110113 in words is "two hundred fifty-five billion, one million, one hundred ten thousand, one hundred thirteen".