Base | Representation |
---|---|
bin | 1110110101111111011… |
… | …0111101011000110111 |
3 | 220101020011202221111010 |
4 | 3231133312331120313 |
5 | 13134230344010312 |
6 | 313052305243303 |
7 | 24265263253230 |
oct | 3553766753067 |
9 | 811204687433 |
10 | 255011313207 |
11 | 99171269012 |
12 | 4150a933533 |
13 | 1b08037bc91 |
14 | c4b21ba087 |
15 | 6977c5793c |
hex | 3b5fdbd637 |
255011313207 has 32 divisors (see below), whose sum is σ = 401786832384. Its totient is φ = 140837875200.
The previous prime is 255011313199. The next prime is 255011313229. The reversal of 255011313207 is 702313110552.
It is not a de Polignac number, because 255011313207 - 23 = 255011313199 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255011313287) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1291894 + ... + 1476147.
It is an arithmetic number, because the mean of its divisors is an integer number (12555838512).
Almost surely, 2255011313207 is an apocalyptic number.
255011313207 is a deficient number, since it is larger than the sum of its proper divisors (146775519177).
255011313207 is a wasteful number, since it uses less digits than its factorization.
255011313207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2768199.
The product of its (nonzero) digits is 6300, while the sum is 30.
Adding to 255011313207 its reverse (702313110552), we get a palindrome (957324423759).
The spelling of 255011313207 in words is "two hundred fifty-five billion, eleven million, three hundred thirteen thousand, two hundred seven".
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