255030341213031 has 4 divisors (see below), whose sum is σ = 340040454950712. Its totient is φ = 170020227475352.

The previous prime is 255030341212991. The next prime is 255030341213107. The reversal of 255030341213031 is 130312143030552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255030341213031 - 2⁷ = 255030341212903 is a prime.

It is a super-2 number, since 2×255030341213031² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255030341212983 and 255030341213001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255030341213231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42505056868836 + ... + 42505056868841.

It is an arithmetic number, because the mean of its divisors is an integer number (85010113737678).

Almost surely, 2^{255030341213031} is an apocalyptic number.

255030341213031 is a deficient number, since it is larger than the sum of its proper divisors (85010113737681).

255030341213031 is an equidigital number, since it uses as much as digits as its factorization.

255030341213031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85010113737680.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 255030341213031 its reverse (130312143030552), we get a palindrome (385342484243583).

The spelling of 255030341213031 in words is "two hundred fifty-five trillion, thirty billion, three hundred forty-one million, two hundred thirteen thousand, thirty-one".