Base | Representation |
---|---|
bin | 111001111111001011100000… |
… | …111001010001110000011011 |
3 | 1020102222122212222020210000220 |
4 | 321333023200321101300123 |
5 | 231411404114322310321 |
6 | 2302223153224531123 |
7 | 104501222412616464 |
oct | 7177134071216033 |
9 | 1212878788223026 |
10 | 255030341213211 |
11 | 7429583aa95513 |
12 | 2472a709320aa3 |
13 | ac3c347a38ac5 |
14 | 46d976a47dd6b |
15 | 1e73dcee999c6 |
hex | e7f2e0e51c1b |
255030341213211 has 8 divisors (see below), whose sum is σ = 340040642244624. Its totient is φ = 170020133828640.
The previous prime is 255030341213173. The next prime is 255030341213231. The reversal of 255030341213211 is 112312143030552.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 255030341213211 - 26 = 255030341213147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (255030341213231) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16789720 + ... + 28141701.
It is an arithmetic number, because the mean of its divisors is an integer number (42505080280578).
Almost surely, 2255030341213211 is an apocalyptic number.
255030341213211 is a deficient number, since it is larger than the sum of its proper divisors (85010301031413).
255030341213211 is a wasteful number, since it uses less digits than its factorization.
255030341213211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46823421.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 255030341213211 its reverse (112312143030552), we get a palindrome (367342484243763).
The spelling of 255030341213211 in words is "two hundred fifty-five trillion, thirty billion, three hundred forty-one million, two hundred thirteen thousand, two hundred eleven".
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