Search a number
-
+
255031241 is a prime number
BaseRepresentation
bin11110011001101…
…11011111001001
3122202212221002112
433030313133021
51010241444431
641150112105
76214505213
oct1714673711
9582787075
10255031241
11120a5a823
12714ab635
1340ab477a
1425c295b3
15175c9c2b
hexf3377c9

255031241 has 2 divisors, whose sum is σ = 255031242. Its totient is φ = 255031240.

The previous prime is 255031213. The next prime is 255031277. The reversal of 255031241 is 142130552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 149352841 + 105678400 = 12221^2 + 10280^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255031241 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (255031201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127515620 + 127515621.

It is an arithmetic number, because the mean of its divisors is an integer number (127515621).

Almost surely, 2255031241 is an apocalyptic number.

It is an amenable number.

255031241 is a deficient number, since it is larger than the sum of its proper divisors (1).

255031241 is an equidigital number, since it uses as much as digits as its factorization.

255031241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 255031241 is about 15969.6975863665. The cubic root of 255031241 is about 634.1584661289.

Adding to 255031241 its reverse (142130552), we get a palindrome (397161793).

The spelling of 255031241 in words is "two hundred fifty-five million, thirty-one thousand, two hundred forty-one".