255033133001035 has 4 divisors (see below), whose sum is σ = 306039759601248. Its totient is φ = 204026506400824.

The previous prime is 255033133001027. The next prime is 255033133001047. The reversal of 255033133001035 is 530100331330552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255033133001035 - 2³ = 255033133001027 is a prime.

It is a super-2 number, since 2×255033133001035² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25503313300099 + ... + 25503313300108.

It is an arithmetic number, because the mean of its divisors is an integer number (76509939900312).

Almost surely, 2^{255033133001035} is an apocalyptic number.

255033133001035 is a deficient number, since it is larger than the sum of its proper divisors (51006626600213).

255033133001035 is an equidigital number, since it uses as much as digits as its factorization.

255033133001035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51006626600212.

The product of its (nonzero) digits is 60750, while the sum is 34.

Adding to 255033133001035 its reverse (530100331330552), we get a palindrome (785133464331587).

The spelling of 255033133001035 in words is "two hundred fifty-five trillion, thirty-three billion, one hundred thirty-three million, one thousand, thirty-five".