Base | Representation |
---|---|
bin | 111001111111001111000111… |
… | …001100011111110101101111 |
3 | 1020110000000212020200001121020 |
4 | 321333033013030133311233 |
5 | 231411440022440330221 |
6 | 2302225032451305223 |
7 | 104501420230432125 |
oct | 7177170714376557 |
9 | 1213000766601536 |
10 | 255034205011311 |
11 | 74297443001190 |
12 | 2472b4072ab213 |
13 | ac3c81237cb7b |
14 | 46d9a1569b915 |
15 | 1e740592b8ac6 |
hex | e7f3c731fd6f |
255034205011311 has 16 divisors (see below), whose sum is σ = 370979730651648. Its totient is φ = 154557481939200.
The previous prime is 255034205011303. The next prime is 255034205011321. The reversal of 255034205011311 is 113110502430552.
It is not a de Polignac number, because 255034205011311 - 23 = 255034205011303 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255034205011321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216977911 + ... + 218150136.
It is an arithmetic number, because the mean of its divisors is an integer number (23186233165728).
Almost surely, 2255034205011311 is an apocalyptic number.
255034205011311 is a deficient number, since it is larger than the sum of its proper divisors (115945525640337).
255034205011311 is a wasteful number, since it uses less digits than its factorization.
255034205011311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 435145822.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 255034205011311 its reverse (113110502430552), we get a palindrome (368144707441863).
The spelling of 255034205011311 in words is "two hundred fifty-five trillion, thirty-four billion, two hundred five million, eleven thousand, three hundred eleven".
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