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255039931 is a prime number
BaseRepresentation
bin11110011001110…
…01100110111011
3122202220101000101
433030321212323
51010242234211
641150220231
76214542436
oct1714714673
9582811011
10255039931
11120a66303
12714b4677
1340ab8703
1425c2c81d
15175cc5c1
hexf3399bb

255039931 has 2 divisors, whose sum is σ = 255039932. Its totient is φ = 255039930.

The previous prime is 255039929. The next prime is 255039959. The reversal of 255039931 is 139930552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255039931 - 21 = 255039929 is a prime.

It is a super-2 number, since 2×2550399312 = 130090732808969522, which contains 22 as substring.

Together with 255039929, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (255039901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127519965 + 127519966.

It is an arithmetic number, because the mean of its divisors is an integer number (127519966).

Almost surely, 2255039931 is an apocalyptic number.

255039931 is a deficient number, since it is larger than the sum of its proper divisors (1).

255039931 is an equidigital number, since it uses as much as digits as its factorization.

255039931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36450, while the sum is 37.

The square root of 255039931 is about 15969.9696618372. The cubic root of 255039931 is about 634.1656688732.

It can be divided in two parts, 255039 and 931, that added together give a triangular number (255970 = T715).

The spelling of 255039931 in words is "two hundred fifty-five million, thirty-nine thousand, nine hundred thirty-one".