Base | Representation |
---|---|
bin | 111001111111011000011000… |
… | …000010010100001110010111 |
3 | 1020110000222112102020101112102 |
4 | 321333120120002110032113 |
5 | 231412120410203401013 |
6 | 2302233355433312315 |
7 | 104502221553054233 |
oct | 7177303002241627 |
9 | 1213028472211472 |
10 | 255044151231383 |
11 | 742a0687423578 |
12 | 2473132226569b |
13 | ac40738b8a5a7 |
14 | 46da2ba6215c3 |
15 | 1e7443c5a1d58 |
hex | e7f618094397 |
255044151231383 has 2 divisors, whose sum is σ = 255044151231384. Its totient is φ = 255044151231382.
The previous prime is 255044151231329. The next prime is 255044151231557. The reversal of 255044151231383 is 383132151440552.
255044151231383 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255044151231383 - 28 = 255044151231127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255044151233383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522075615691 + 127522075615692.
It is an arithmetic number, because the mean of its divisors is an integer number (127522075615692).
Almost surely, 2255044151231383 is an apocalyptic number.
255044151231383 is a deficient number, since it is larger than the sum of its proper divisors (1).
255044151231383 is an equidigital number, since it uses as much as digits as its factorization.
255044151231383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728000, while the sum is 47.
The spelling of 255044151231383 in words is "two hundred fifty-five trillion, forty-four billion, one hundred fifty-one million, two hundred thirty-one thousand, three hundred eighty-three".
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