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2550454451 = 2672995419
BaseRepresentation
bin1001100000000100…
…1101100010110011
320120202010111202222
42120001031202303
520210404020301
61101025031255
7120126335156
oct23001154263
96522114688
102550454451
1110997351a6
125b218552b
1331851665c
141a2a25c9d
15edd9531b
hex9804d8b3

2550454451 has 4 divisors (see below), whose sum is σ = 2550576600. Its totient is φ = 2550332304.

The previous prime is 2550454433. The next prime is 2550454453. The reversal of 2550454451 is 1544540552.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2550454451 - 222 = 2546260147 is a prime.

It is a super-2 number, since 2×25504544512 = 13009635813251422802, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2550454453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20981 + ... + 74438.

It is an arithmetic number, because the mean of its divisors is an integer number (637644150).

Almost surely, 22550454451 is an apocalyptic number.

2550454451 is a deficient number, since it is larger than the sum of its proper divisors (122149).

2550454451 is an equidigital number, since it uses as much as digits as its factorization.

2550454451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122148.

The product of its (nonzero) digits is 80000, while the sum is 35.

The square root of 2550454451 is about 50502.0242267575. The cubic root of 2550454451 is about 1366.2783626627.

The spelling of 2550454451 in words is "two billion, five hundred fifty million, four hundred fifty-four thousand, four hundred fifty-one".

Divisors: 1 26729 95419 2550454451