Base | Representation |
---|---|
bin | 111001111111011110000001… |
… | …111101110110100010011100 |
3 | 1020110001120012121010012022211 |
4 | 321333132001331312202130 |
5 | 231412220324143212104 |
6 | 2302240242145250204 |
7 | 104502525204544636 |
oct | 7177360175664234 |
9 | 1213046177105284 |
10 | 255050223413404 |
11 | 742a3212a75821 |
12 | 24732537933964 |
13 | ac41195baa0c3 |
14 | 46da6d4c5da56 |
15 | 1e746956e6e04 |
hex | e7f781f7689c |
255050223413404 has 48 divisors (see below), whose sum is σ = 454762629529600. Its totient is φ = 125139724834176.
The previous prime is 255050223413347. The next prime is 255050223413417. The reversal of 255050223413404 is 404314322050552.
It is a super-3 number, since 3×2550502234134043 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39792712 + ... + 45755440.
Almost surely, 2255050223413404 is an apocalyptic number.
It is an amenable number.
255050223413404 is a deficient number, since it is larger than the sum of its proper divisors (199712406116196).
255050223413404 is a wasteful number, since it uses less digits than its factorization.
255050223413404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5963642 (or 5963640 counting only the distinct ones).
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 255050223413404 its reverse (404314322050552), we get a palindrome (659364545463956).
The spelling of 255050223413404 in words is "two hundred fifty-five trillion, fifty billion, two hundred twenty-three million, four hundred thirteen thousand, four hundred four".
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