Base | Representation |
---|---|
bin | 10111110000001110… |
… | …000110000011100101 |
3 | 2102211111021110012012 |
4 | 113300032012003211 |
5 | 404213244010031 |
6 | 15414502004005 |
7 | 1562016313445 |
oct | 276016060345 |
9 | 72744243165 |
10 | 25505063141 |
11 | a8a8a41488 |
12 | 4b39716605 |
13 | 253607204c |
14 | 133d49a125 |
15 | 9e41dab2b |
hex | 5f03860e5 |
25505063141 has 2 divisors, whose sum is σ = 25505063142. Its totient is φ = 25505063140.
The previous prime is 25505063137. The next prime is 25505063167. The reversal of 25505063141 is 14136050552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16756266916 + 8748796225 = 129446^2 + 93535^2 .
It is a cyclic number.
It is not a de Polignac number, because 25505063141 - 22 = 25505063137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25505063098 and 25505063107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25505063641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12752531570 + 12752531571.
It is an arithmetic number, because the mean of its divisors is an integer number (12752531571).
Almost surely, 225505063141 is an apocalyptic number.
It is an amenable number.
25505063141 is a deficient number, since it is larger than the sum of its proper divisors (1).
25505063141 is an equidigital number, since it uses as much as digits as its factorization.
25505063141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 25505063141 in words is "twenty-five billion, five hundred five million, sixty-three thousand, one hundred forty-one".
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