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2550560341 = 7364365763
BaseRepresentation
bin1001100000000110…
…0111011001010101
320120202022220000211
42120001213121111
520210420412331
61101031205421
7120130255660
oct23001473125
96522286024
102550560341
1110997a780a
125b2216871
13318552904
141a2a526d7
15eddb68b1
hex98067655

2550560341 has 4 divisors (see below), whose sum is σ = 2914926112. Its totient is φ = 2186194572.

The previous prime is 2550560333. The next prime is 2550560357. The reversal of 2550560341 is 1430650552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2550560341 - 23 = 2550560333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2550560381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182182875 + ... + 182182888.

It is an arithmetic number, because the mean of its divisors is an integer number (728731528).

Almost surely, 22550560341 is an apocalyptic number.

It is an amenable number.

2550560341 is a deficient number, since it is larger than the sum of its proper divisors (364365771).

2550560341 is an equidigital number, since it uses as much as digits as its factorization.

2550560341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 364365770.

The product of its (nonzero) digits is 18000, while the sum is 31.

The square root of 2550560341 is about 50503.0725896950. The cubic root of 2550560341 is about 1366.2972708241.

The spelling of 2550560341 in words is "two billion, five hundred fifty million, five hundred sixty thousand, three hundred forty-one".

Divisors: 1 7 364365763 2550560341