Base | Representation |
---|---|
bin | 100101000111011011110… |
… | …101000101001010100111 |
3 | 100000211112221220110220221 |
4 | 211013123311011022213 |
5 | 313242114023402443 |
6 | 5231421533505211 |
7 | 352163224000603 |
oct | 45073365051247 |
9 | 10024487813827 |
10 | 2550603731623 |
11 | 8a3783348892 |
12 | 3523a8042207 |
13 | 1566a05560bc |
14 | 8b64267c503 |
15 | 465314adeed |
hex | 251dbd452a7 |
2550603731623 has 2 divisors, whose sum is σ = 2550603731624. Its totient is φ = 2550603731622.
The previous prime is 2550603731573. The next prime is 2550603731639. The reversal of 2550603731623 is 3261373060552.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2550603731623 is a prime.
It is a super-2 number, since 2×25506037316232 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2550603731623.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2550603731023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275301865811 + 1275301865812.
It is an arithmetic number, because the mean of its divisors is an integer number (1275301865812).
Almost surely, 22550603731623 is an apocalyptic number.
2550603731623 is a deficient number, since it is larger than the sum of its proper divisors (1).
2550603731623 is an equidigital number, since it uses as much as digits as its factorization.
2550603731623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 43.
The spelling of 2550603731623 in words is "two trillion, five hundred fifty billion, six hundred three million, seven hundred thirty-one thousand, six hundred twenty-three".
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