Base | Representation |
---|---|
bin | 100101000111110000110… |
… | …001110011101101000111 |
3 | 100000212110110020200022201 |
4 | 211013300301303231013 |
5 | 313243324012221312 |
6 | 5231520450535331 |
7 | 352205022252016 |
oct | 45076061635507 |
9 | 10025413220281 |
10 | 2550955195207 |
11 | 8a3943782661 |
12 | 352485897547 |
13 | 156728302513 |
14 | 8b67720aa7d |
15 | 46552286557 |
hex | 251f0c73b47 |
2550955195207 has 2 divisors, whose sum is σ = 2550955195208. Its totient is φ = 2550955195206.
The previous prime is 2550955195177. The next prime is 2550955195249. The reversal of 2550955195207 is 7025915590552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2550955195207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2550955195297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275477597603 + 1275477597604.
It is an arithmetic number, because the mean of its divisors is an integer number (1275477597604).
Almost surely, 22550955195207 is an apocalyptic number.
2550955195207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2550955195207 is an equidigital number, since it uses as much as digits as its factorization.
2550955195207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7087500, while the sum is 55.
The spelling of 2550955195207 in words is "two trillion, five hundred fifty billion, nine hundred fifty-five million, one hundred ninety-five thousand, two hundred seven".
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