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255100055413 = 736442865059
BaseRepresentation
bin1110110110010100100…
…1011110111101110101
3220101110100202111220111
43231211021132331311
513134421103233123
6313105155303021
724300421456660
oct3554511367565
9811410674814
10255100055413
1199207370385
12415345aaa71
131b095880568
14c4bdcba6d7
15698093690d
hex3b6525ef75

255100055413 has 4 divisors (see below), whose sum is σ = 291542920480. Its totient is φ = 218657190348.

The previous prime is 255100055407. The next prime is 255100055437. The reversal of 255100055413 is 314550001552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255100055413 - 217 = 255099924341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255100055213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18221432523 + ... + 18221432536.

It is an arithmetic number, because the mean of its divisors is an integer number (72885730120).

Almost surely, 2255100055413 is an apocalyptic number.

It is an amenable number.

255100055413 is a deficient number, since it is larger than the sum of its proper divisors (36442865067).

255100055413 is an equidigital number, since it uses as much as digits as its factorization.

255100055413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36442865066.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 255100055413 its reverse (314550001552), we get a palindrome (569650056965).

The spelling of 255100055413 in words is "two hundred fifty-five billion, one hundred million, fifty-five thousand, four hundred thirteen".

Divisors: 1 7 36442865059 255100055413