Base | Representation |
---|---|
bin | 1001100000001111… |
… | …0011001101000001 |
3 | 20120210101222120011 |
4 | 2120003303031001 |
5 | 20211042223433 |
6 | 1101051344521 |
7 | 120135162343 |
oct | 23003631501 |
9 | 6523358504 |
10 | 2551132993 |
11 | 109a058a82 |
12 | 5b2452141 |
13 | 3186c3466 |
14 | 1a2b61293 |
15 | ede7b3cd |
hex | 980f3341 |
2551132993 has 2 divisors, whose sum is σ = 2551132994. Its totient is φ = 2551132992.
The previous prime is 2551132979. The next prime is 2551133047. The reversal of 2551132993 is 3992311552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2495302209 + 55830784 = 49953^2 + 7472^2 .
It is a cyclic number.
It is not a de Polignac number, because 2551132993 - 29 = 2551132481 is a prime.
It is not a weakly prime, because it can be changed into another prime (2551132963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275566496 + 1275566497.
It is an arithmetic number, because the mean of its divisors is an integer number (1275566497).
Almost surely, 22551132993 is an apocalyptic number.
It is an amenable number.
2551132993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2551132993 is an equidigital number, since it uses as much as digits as its factorization.
2551132993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72900, while the sum is 40.
The square root of 2551132993 is about 50508.7417483350. The cubic root of 2551132993 is about 1366.3995168945.
The spelling of 2551132993 in words is "two billion, five hundred fifty-one million, one hundred thirty-two thousand, nine hundred ninety-three".
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