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255121706257 = 1123192882387
BaseRepresentation
bin1110110110011001110…
…0000100110100010001
3220101111212111111021121
43231212130010310101
513134442124100012
6313111251322241
724301103502655
oct3554634046421
9811455444247
10255121706257
1199218608a40
124153b8b0381
131b09a1c1202
14c4c2b14a65
1569827b1a07
hex3b66704d11

255121706257 has 4 divisors (see below), whose sum is σ = 278314588656. Its totient is φ = 231928823860.

The previous prime is 255121706249. The next prime is 255121706261. The reversal of 255121706257 is 752607121552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 255121706257 - 23 = 255121706249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (255121706227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11596441183 + ... + 11596441204.

It is an arithmetic number, because the mean of its divisors is an integer number (69578647164).

Almost surely, 2255121706257 is an apocalyptic number.

It is an amenable number.

255121706257 is a deficient number, since it is larger than the sum of its proper divisors (23192882399).

255121706257 is a wasteful number, since it uses less digits than its factorization.

255121706257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23192882398.

The product of its (nonzero) digits is 294000, while the sum is 43.

The spelling of 255121706257 in words is "two hundred fifty-five billion, one hundred twenty-one million, seven hundred six thousand, two hundred fifty-seven".

Divisors: 1 11 23192882387 255121706257