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255124226214047 is a prime number
BaseRepresentation
bin111010000000100010111100…
…111000001000100010011111
31020110022122012222102222102002
4322000202330320020202133
5231414423403402322142
62302334241310152515
7104511055105144211
oct7200427470104237
91213278188388362
10255124226214047
11743216386941a3
122474494b1b273b
13ac4815a6b6b38
1447001153185b1
151e76577432a32
hexe808bce0889f

255124226214047 has 2 divisors, whose sum is σ = 255124226214048. Its totient is φ = 255124226214046.

The previous prime is 255124226213999. The next prime is 255124226214059. The reversal of 255124226214047 is 740412622421552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255124226214047 - 214 = 255124226197663 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255124226213992 and 255124226214010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255124226244047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127562113107023 + 127562113107024.

It is an arithmetic number, because the mean of its divisors is an integer number (127562113107024).

Almost surely, 2255124226214047 is an apocalyptic number.

255124226214047 is a deficient number, since it is larger than the sum of its proper divisors (1).

255124226214047 is an equidigital number, since it uses as much as digits as its factorization.

255124226214047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2150400, while the sum is 47.

Adding to 255124226214047 its reverse (740412622421552), we get a palindrome (995536848635599).

The spelling of 255124226214047 in words is "two hundred fifty-five trillion, one hundred twenty-four billion, two hundred twenty-six million, two hundred fourteen thousand, forty-seven".