Base | Representation |
---|---|
bin | 1011100110100000110001… |
… | …11111111001000010101111 |
3 | 10100022222021202001101111211 |
4 | 11303100120333321002233 |
5 | 11320444122413441033 |
6 | 130132143043055251 |
7 | 5242135104422116 |
oct | 563203077710257 |
9 | 110288252041454 |
10 | 25512525140143 |
11 | 814688a371188 |
12 | 2a405b9071527 |
13 | 1130a893a55a2 |
14 | 642b544a2c7d |
15 | 2e398cadd2cd |
hex | 173418ff90af |
25512525140143 has 2 divisors, whose sum is σ = 25512525140144. Its totient is φ = 25512525140142.
The previous prime is 25512525140131. The next prime is 25512525140191. The reversal of 25512525140143 is 34104152521552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25512525140143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25512525140096 and 25512525140105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25512525140743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12756262570071 + 12756262570072.
It is an arithmetic number, because the mean of its divisors is an integer number (12756262570072).
Almost surely, 225512525140143 is an apocalyptic number.
25512525140143 is a deficient number, since it is larger than the sum of its proper divisors (1).
25512525140143 is an equidigital number, since it uses as much as digits as its factorization.
25512525140143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 25512525140143 its reverse (34104152521552), we get a palindrome (59616677661695).
The spelling of 25512525140143 in words is "twenty-five trillion, five hundred twelve billion, five hundred twenty-five million, one hundred forty thousand, one hundred forty-three".
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