Base | Representation |
---|---|
bin | 1001100000010011… |
… | …0101101000011001 |
3 | 20120210220210210111 |
4 | 2120010311220121 |
5 | 20211124430311 |
6 | 1101101244321 |
7 | 120140404531 |
oct | 23004655031 |
9 | 6523823714 |
10 | 2551405081 |
11 | 109a224445 |
12 | 5b25636a1 |
13 | 31878a264 |
14 | 1a2bd24c1 |
15 | eded1d21 |
hex | 98135a19 |
2551405081 has 2 divisors, whose sum is σ = 2551405082. Its totient is φ = 2551405080.
The previous prime is 2551405057. The next prime is 2551405117. The reversal of 2551405081 is 1805041552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2511513225 + 39891856 = 50115^2 + 6316^2 .
It is a cyclic number.
It is not a de Polignac number, because 2551405081 - 27 = 2551404953 is a prime.
It is a super-2 number, since 2×25514050812 = 13019335774705233122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2551405981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275702540 + 1275702541.
It is an arithmetic number, because the mean of its divisors is an integer number (1275702541).
Almost surely, 22551405081 is an apocalyptic number.
It is an amenable number.
2551405081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2551405081 is an equidigital number, since it uses as much as digits as its factorization.
2551405081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8000, while the sum is 31.
The square root of 2551405081 is about 50511.4351508646. The cubic root of 2551405081 is about 1366.4480923962.
The spelling of 2551405081 in words is "two billion, five hundred fifty-one million, four hundred five thousand, eighty-one".
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