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255141406441 is a prime number
BaseRepresentation
bin1110110110011110011…
…1001110011011101001
3220101120020120100212001
43231213213032123221
513140012200001231
6313113233451001
724301433112625
oct3554747163351
9811506510761
10255141406441
1199228743a89
1241546410a61
131b0a12cb01c
14c4c55a2185
1569843a3b61
hex3b679ce6e9

255141406441 has 2 divisors, whose sum is σ = 255141406442. Its totient is φ = 255141406440.

The previous prime is 255141406433. The next prime is 255141406469. The reversal of 255141406441 is 144604141552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 161526825216 + 93614581225 = 401904^2 + 305965^2 .

It is a cyclic number.

It is not a de Polignac number, because 255141406441 - 23 = 255141406433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 255141406441.

It is not a weakly prime, because it can be changed into another prime (255141407441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127570703220 + 127570703221.

It is an arithmetic number, because the mean of its divisors is an integer number (127570703221).

Almost surely, 2255141406441 is an apocalyptic number.

It is an amenable number.

255141406441 is a deficient number, since it is larger than the sum of its proper divisors (1).

255141406441 is an equidigital number, since it uses as much as digits as its factorization.

255141406441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 76800, while the sum is 37.

Adding to 255141406441 its reverse (144604141552), we get a palindrome (399745547993).

The spelling of 255141406441 in words is "two hundred fifty-five billion, one hundred forty-one million, four hundred six thousand, four hundred forty-one".