Base | Representation |
---|---|
bin | 1110110110011110011… |
… | …1001110011011100001 |
3 | 220101120020120100211202 |
4 | 3231213213032123201 |
5 | 13140012200001213 |
6 | 313113233450545 |
7 | 24301433112614 |
oct | 3554747163341 |
9 | 811506510752 |
10 | 255141406433 |
11 | 99228743a81 |
12 | 41546410a55 |
13 | 1b0a12cb014 |
14 | c4c55a217b |
15 | 69843a3b58 |
hex | 3b679ce6e1 |
255141406433 has 2 divisors, whose sum is σ = 255141406434. Its totient is φ = 255141406432.
The previous prime is 255141406409. The next prime is 255141406441. The reversal of 255141406433 is 334604141552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 144630371809 + 110511034624 = 380303^2 + 332432^2 .
It is a cyclic number.
It is not a de Polignac number, because 255141406433 - 212 = 255141402337 is a prime.
It is not a weakly prime, because it can be changed into another prime (255141406133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127570703216 + 127570703217.
It is an arithmetic number, because the mean of its divisors is an integer number (127570703217).
Almost surely, 2255141406433 is an apocalyptic number.
It is an amenable number.
255141406433 is a deficient number, since it is larger than the sum of its proper divisors (1).
255141406433 is an equidigital number, since it uses as much as digits as its factorization.
255141406433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 255141406433 its reverse (334604141552), we get a palindrome (589745547985).
The spelling of 255141406433 in words is "two hundred fifty-five billion, one hundred forty-one million, four hundred six thousand, four hundred thirty-three".
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