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2551433 is a prime number
BaseRepresentation
bin1001101110111010001001
311210121220112
421232322021
51123121213
6130404105
730454403
oct11567211
94717815
102551433
111492a25
12a30635
136b4431
144a5b73
15355ea8
hex26ee89

2551433 has 2 divisors, whose sum is σ = 2551434. Its totient is φ = 2551432.

The previous prime is 2551429. The next prime is 2551441. The reversal of 2551433 is 3341552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2550409 + 1024 = 1597^2 + 32^2 .

It is a cyclic number.

It is not a de Polignac number, because 2551433 - 22 = 2551429 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2551399 and 2551408.

It is not a weakly prime, because it can be changed into another prime (2551403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275716 + 1275717.

It is an arithmetic number, because the mean of its divisors is an integer number (1275717).

22551433 is an apocalyptic number.

It is an amenable number.

2551433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2551433 is an equidigital number, since it uses as much as digits as its factorization.

2551433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1800, while the sum is 23.

The square root of 2551433 is about 1597.3205689529. The cubic root of 2551433 is about 136.6453076542.

Adding to 2551433 its reverse (3341552), we get a palindrome (5892985).

The spelling of 2551433 in words is "two million, five hundred fifty-one thousand, four hundred thirty-three".