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255202041 = 385067347
BaseRepresentation
bin11110011011000…
…01001011111001
3122210012121101110
433031201023321
51010312431131
641153510533
76216116163
oct1715411371
9583177343
10255202041
11121067086
1271572449
1340b44433
1425c71933
1517610646
hexf3612f9

255202041 has 4 divisors (see below), whose sum is σ = 340269392. Its totient is φ = 170134692.

The previous prime is 255202037. The next prime is 255202063. The reversal of 255202041 is 140202552.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 255202041 - 22 = 255202037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 255201999 and 255202017.

It is not an unprimeable number, because it can be changed into a prime (255202021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42533671 + ... + 42533676.

It is an arithmetic number, because the mean of its divisors is an integer number (85067348).

Almost surely, 2255202041 is an apocalyptic number.

It is an amenable number.

255202041 is a deficient number, since it is larger than the sum of its proper divisors (85067351).

255202041 is an equidigital number, since it uses as much as digits as its factorization.

255202041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85067350.

The product of its (nonzero) digits is 800, while the sum is 21.

The square root of 255202041 is about 15975.0443191873. The cubic root of 255202041 is about 634.3000044681.

Adding to 255202041 its reverse (140202552), we get a palindrome (395404593).

The spelling of 255202041 in words is "two hundred fifty-five million, two hundred two thousand, forty-one".

Divisors: 1 3 85067347 255202041