Base | Representation |
---|---|
bin | 100101001000110000110… |
… | …111100100010111111111 |
3 | 100000222020101112010122000 |
4 | 211020300313210113333 |
5 | 313303024243301403 |
6 | 5232215301153343 |
7 | 352243456612134 |
oct | 45106067442777 |
9 | 10028211463560 |
10 | 2552030447103 |
11 | 8a4345724295 |
12 | 3527259bb853 |
13 | 156869cc9847 |
14 | 8b739d4658b |
15 | 465b687e7a3 |
hex | 25230de45ff |
2552030447103 has 16 divisors (see below), whose sum is σ = 3780825657600. Its totient is φ = 1701335716920.
The previous prime is 2552030447101. The next prime is 2552030447117. The reversal of 2552030447103 is 3017440302552.
2552030447103 is a `hidden beast` number, since 2 + 5 + 5 + 203 + 0 + 447 + 1 + 0 + 3 = 666.
It is not a de Polignac number, because 2552030447103 - 21 = 2552030447101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2552030447101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2426478 + ... + 3315396.
It is an arithmetic number, because the mean of its divisors is an integer number (236301603600).
Almost surely, 22552030447103 is an apocalyptic number.
2552030447103 is a deficient number, since it is larger than the sum of its proper divisors (1228795210497).
2552030447103 is a wasteful number, since it uses less digits than its factorization.
2552030447103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 995259 (or 995253 counting only the distinct ones).
The product of its (nonzero) digits is 100800, while the sum is 36.
Adding to 2552030447103 its reverse (3017440302552), we get a palindrome (5569470749655).
The spelling of 2552030447103 in words is "two trillion, five hundred fifty-two billion, thirty million, four hundred forty-seven thousand, one hundred three".
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