Base | Representation |
---|---|
bin | 1110110110101111100… |
… | …0110111100101100001 |
3 | 220101202020112211020102 |
4 | 3231223320313211201 |
5 | 13140134030442241 |
6 | 313124315152145 |
7 | 24303263620406 |
oct | 3555370674541 |
9 | 811666484212 |
10 | 255213140321 |
11 | 99265189787 |
12 | 41566445655 |
13 | 1b0b3125ac9 |
14 | c4d0d162ad |
15 | 698a82339b |
hex | 3b6be37961 |
255213140321 has 4 divisors (see below), whose sum is σ = 255724590000. Its totient is φ = 254701690644.
The previous prime is 255213140291. The next prime is 255213140323. The reversal of 255213140321 is 123041312552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255213140321 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (255213140323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255724091 + ... + 255725088.
It is an arithmetic number, because the mean of its divisors is an integer number (63931147500).
Almost surely, 2255213140321 is an apocalyptic number.
It is an amenable number.
255213140321 is a deficient number, since it is larger than the sum of its proper divisors (511449679).
255213140321 is an equidigital number, since it uses as much as digits as its factorization.
255213140321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 511449678.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 255213140321 its reverse (123041312552), we get a palindrome (378254452873).
The spelling of 255213140321 in words is "two hundred fifty-five billion, two hundred thirteen million, one hundred forty thousand, three hundred twenty-one".
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