Base | Representation |
---|---|
bin | 111010000001110110110101… |
… | …111001011000000101001001 |
3 | 1020110122020201121120202222100 |
4 | 322001312311321120011021 |
5 | 231422412343133200203 |
6 | 2302443455445144013 |
7 | 104520424232535252 |
oct | 7201666571300511 |
9 | 1213566647522870 |
10 | 255214303412553 |
11 | 74356861942701 |
12 | 2475a2a99bb009 |
13 | ac537b44c82b4 |
14 | 470461c58db29 |
15 | 1e78a9a45cea3 |
hex | e81db5e58149 |
255214303412553 has 6 divisors (see below), whose sum is σ = 368642882707034. Its totient is φ = 170142868941696.
The previous prime is 255214303412531. The next prime is 255214303412573. The reversal of 255214303412553 is 355214303412552.
255214303412553 is a `hidden beast` number, since 2 + 5 + 5 + 21 + 4 + 30 + 3 + 41 + 2 + 553 = 666.
It can be written as a sum of positive squares in only one way, i.e., 173996861679369 + 81217441733184 = 13190787^2 + 9012072^2 .
It is not a de Polignac number, because 255214303412553 - 25 = 255214303412521 is a prime.
It is a super-2 number, since 2×2552143034125532 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 255214303412499 and 255214303412508.
It is not an unprimeable number, because it can be changed into a prime (255214303412573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 14178572411800 + ... + 14178572411817.
Almost surely, 2255214303412553 is an apocalyptic number.
It is an amenable number.
255214303412553 is a deficient number, since it is larger than the sum of its proper divisors (113428579294481).
255214303412553 is a wasteful number, since it uses less digits than its factorization.
255214303412553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28357144823623 (or 28357144823620 counting only the distinct ones).
The product of its (nonzero) digits is 2160000, while the sum is 45.
Subtracting 255214303412553 from its reverse (355214303412552), we obtain a palindrome (99999999999999).
The spelling of 255214303412553 in words is "two hundred fifty-five trillion, two hundred fourteen billion, three hundred three million, four hundred twelve thousand, five hundred fifty-three".
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