Base | Representation |
---|---|
bin | 1011100110110010100000… |
… | …10101010111010000100001 |
3 | 10100100212212002102122112101 |
4 | 11303121100111113100201 |
5 | 11321123121110403101 |
6 | 130140355341330401 |
7 | 5242623012630601 |
oct | 563312025272041 |
9 | 110325762378471 |
10 | 25522043450401 |
11 | 814a9241955a3 |
12 | 2a42414866a01 |
13 | 113194534bc34 |
14 | 6433b8678c01 |
15 | 2e3d4854d401 |
hex | 173650557421 |
25522043450401 has 8 divisors (see below), whose sum is σ = 27023822259840. Its totient is φ = 24020318211648.
The previous prime is 25522043450399. The next prime is 25522043450411. The reversal of 25522043450401 is 10405434022552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 25522043450401 - 21 = 25522043450399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (25522043450411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12409741 + ... + 14319418.
It is an arithmetic number, because the mean of its divisors is an integer number (3377977782480).
Almost surely, 225522043450401 is an apocalyptic number.
It is an amenable number.
25522043450401 is a deficient number, since it is larger than the sum of its proper divisors (1501778809439).
25522043450401 is a wasteful number, since it uses less digits than its factorization.
25522043450401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26785343.
The product of its (nonzero) digits is 192000, while the sum is 37.
Adding to 25522043450401 its reverse (10405434022552), we get a palindrome (35927477472953).
The spelling of 25522043450401 in words is "twenty-five trillion, five hundred twenty-two billion, forty-three million, four hundred fifty thousand, four hundred one".
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