Base | Representation |
---|---|
bin | 100101001001000011010… |
… | …100011010111010011101 |
3 | 100001000000222000001221102 |
4 | 211021003110122322131 |
5 | 313304143020003123 |
6 | 5232310120042445 |
7 | 352254236021000 |
oct | 45110324327235 |
9 | 10030028001842 |
10 | 2552340000413 |
11 | 8a4494433275 |
12 | 3527b1603425 |
13 | 1568b9190a98 |
14 | 8b7690c5537 |
15 | 465d3b29028 |
hex | 2524351ae9d |
2552340000413 has 16 divisors (see below), whose sum is σ = 3026938800000. Its totient is φ = 2150639983296.
The previous prime is 2552340000391. The next prime is 2552340000451. The reversal of 2552340000413 is 3140000432552.
It is a happy number.
It is not a de Polignac number, because 2552340000413 - 28 = 2552340000157 is a prime.
It is a super-3 number, since 3×25523400004133 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2552340000473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63040988 + ... + 63081461.
It is an arithmetic number, because the mean of its divisors is an integer number (189183675000).
Almost surely, 22552340000413 is an apocalyptic number.
It is an amenable number.
2552340000413 is a deficient number, since it is larger than the sum of its proper divisors (474598799587).
2552340000413 is an equidigital number, since it uses as much as digits as its factorization.
2552340000413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126122529 (or 126122515 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 2552340000413 its reverse (3140000432552), we get a palindrome (5692340432965).
The spelling of 2552340000413 in words is "two trillion, five hundred fifty-two billion, three hundred forty million, four hundred thirteen", and thus it is an aban number.
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