Base | Representation |
---|---|
bin | 111010000010001010011100… |
… | …000101000111101111010011 |
3 | 1020110201021001001021021111012 |
4 | 322002022130011013233103 |
5 | 231423233441322321321 |
6 | 2302501255430041135 |
7 | 104522100534232601 |
oct | 7202123405075723 |
9 | 1213637031237435 |
10 | 255235345120211 |
11 | 7436477a392045 |
12 | 247623a07a91ab |
13 | ac55788953ca1 |
14 | 4705656d5c871 |
15 | 1e793cc89805b |
hex | e8229c147bd3 |
255235345120211 has 2 divisors, whose sum is σ = 255235345120212. Its totient is φ = 255235345120210.
The previous prime is 255235345120181. The next prime is 255235345120243. The reversal of 255235345120211 is 112021543532552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255235345120211 - 246 = 184866600942547 is a prime.
It is not a weakly prime, because it can be changed into another prime (255235345120271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127617672560105 + 127617672560106.
It is an arithmetic number, because the mean of its divisors is an integer number (127617672560106).
Almost surely, 2255235345120211 is an apocalyptic number.
255235345120211 is a deficient number, since it is larger than the sum of its proper divisors (1).
255235345120211 is an equidigital number, since it uses as much as digits as its factorization.
255235345120211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 255235345120211 its reverse (112021543532552), we get a palindrome (367256888652763).
The spelling of 255235345120211 in words is "two hundred fifty-five trillion, two hundred thirty-five billion, three hundred forty-five million, one hundred twenty thousand, two hundred eleven".
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