Base | Representation |
---|---|
bin | 1110110110110110001… |
… | …1101001011111010101 |
3 | 220101211012012221120212 |
4 | 3231231203221133111 |
5 | 13140213212210424 |
6 | 313131155135205 |
7 | 24304053552644 |
oct | 3555543513725 |
9 | 811735187525 |
10 | 255241131989 |
11 | 99279a68298 |
12 | 415738a4505 |
13 | 1b0b8b7691c |
14 | c4d492135b |
15 | 698d00210e |
hex | 3b6d8e97d5 |
255241131989 has 2 divisors, whose sum is σ = 255241131990. Its totient is φ = 255241131988.
The previous prime is 255241131973. The next prime is 255241132049. The reversal of 255241131989 is 989131142552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 223878492964 + 31362639025 = 473158^2 + 177095^2 .
It is a cyclic number.
It is not a de Polignac number, because 255241131989 - 24 = 255241131973 is a prime.
It is a super-2 number, since 2×2552411319892 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255241131289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127620565994 + 127620565995.
It is an arithmetic number, because the mean of its divisors is an integer number (127620565995).
Almost surely, 2255241131989 is an apocalyptic number.
It is an amenable number.
255241131989 is a deficient number, since it is larger than the sum of its proper divisors (1).
255241131989 is an equidigital number, since it uses as much as digits as its factorization.
255241131989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 777600, while the sum is 50.
The spelling of 255241131989 in words is "two hundred fifty-five billion, two hundred forty-one million, one hundred thirty-one thousand, nine hundred eighty-nine".
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