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255255131 is a prime number
BaseRepresentation
bin11110011011011…
…10001001011011
3122210022022012202
433031232021123
51010321131011
641155000415
76216430025
oct1715561133
9583268182
10255255131
111210a2a5a
127159910b
1340b62651
1425c87015
151762123b
hexf36e25b

255255131 has 2 divisors, whose sum is σ = 255255132. Its totient is φ = 255255130.

The previous prime is 255255113. The next prime is 255255151. The reversal of 255255131 is 131552552.

Together with previous prime (255255113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255255131 - 210 = 255254107 is a prime.

It is a super-2 number, since 2×2552551312 = 130310363803654322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 255255094 and 255255103.

It is not a weakly prime, because it can be changed into another prime (255255151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127627565 + 127627566.

It is an arithmetic number, because the mean of its divisors is an integer number (127627566).

Almost surely, 2255255131 is an apocalyptic number.

255255131 is a deficient number, since it is larger than the sum of its proper divisors (1).

255255131 is an equidigital number, since it uses as much as digits as its factorization.

255255131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7500, while the sum is 29.

The square root of 255255131 is about 15976.7058870094. The cubic root of 255255131 is about 634.3439861596.

The spelling of 255255131 in words is "two hundred fifty-five million, two hundred fifty-five thousand, one hundred thirty-one".