Base | Representation |
---|---|
bin | 100101001001101101110… |
… | …011100010111011010111 |
3 | 100001001212122021011221220 |
4 | 211021231303202323113 |
5 | 313312123004142100 |
6 | 5232504541541423 |
7 | 352311012522666 |
oct | 45115563427327 |
9 | 10031778234856 |
10 | 2553052802775 |
11 | 8a481a827232 |
12 | 352970274873 |
13 | 1569a0a63427 |
14 | 8b7d5a32ddd |
15 | 466264c9aa0 |
hex | 2526dce2ed7 |
2553052802775 has 48 divisors (see below), whose sum is σ = 4357474437120. Its totient is φ = 1317624739200.
The previous prime is 2553052802743. The next prime is 2553052802801. The reversal of 2553052802775 is 5772082503552.
2553052802775 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2553052802775 - 25 = 2553052802743 is a prime.
It is a super-2 number, since 2×25530528027752 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 69636349 + ... + 69673001.
It is an arithmetic number, because the mean of its divisors is an integer number (90780717440).
Almost surely, 22553052802775 is an apocalyptic number.
2553052802775 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2553052802775 is a deficient number, since it is larger than the sum of its proper divisors (1804421634345).
2553052802775 is a wasteful number, since it uses less digits than its factorization.
2553052802775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66656 (or 66651 counting only the distinct ones).
The product of its (nonzero) digits is 5880000, while the sum is 51.
The spelling of 2553052802775 in words is "two trillion, five hundred fifty-three billion, fifty-two million, eight hundred two thousand, seven hundred seventy-five".
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