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2553053433 = 37121573973
BaseRepresentation
bin1001100000101100…
…1000000011111001
320120221000112220120
42120023020003321
520212040202213
61101200443453
7120160411320
oct23013100371
96527015816
102553053433
1110a014a917
125b3019589
13318c16608
141a31010b7
15ee20a423
hex982c80f9

2553053433 has 8 divisors (see below), whose sum is σ = 3890367168. Its totient is φ = 1458887664.

The previous prime is 2553053431. The next prime is 2553053443. The reversal of 2553053433 is 3343503552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2553053433 - 21 = 2553053431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2553053394 and 2553053403.

It is not an unprimeable number, because it can be changed into a prime (2553053431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60786966 + ... + 60787007.

It is an arithmetic number, because the mean of its divisors is an integer number (486295896).

Almost surely, 22553053433 is an apocalyptic number.

It is an amenable number.

2553053433 is a deficient number, since it is larger than the sum of its proper divisors (1337313735).

2553053433 is a wasteful number, since it uses less digits than its factorization.

2553053433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121573983.

The product of its (nonzero) digits is 81000, while the sum is 33.

The square root of 2553053433 is about 50527.7491384685. The cubic root of 2553053433 is about 1366.7422966343.

Adding to 2553053433 its reverse (3343503552), we get a palindrome (5896556985).

The spelling of 2553053433 in words is "two billion, five hundred fifty-three million, fifty-three thousand, four hundred thirty-three".

Divisors: 1 3 7 21 121573973 364721919 851017811 2553053433