2553114433 has 4 divisors (see below), whose sum is σ = 2553280048. Its totient is φ = 2552948820.

The previous prime is 2553114397. The next prime is 2553114437. The reversal of 2553114433 is 3344113552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2553114433 is a prime.

It is a super-2 number, since 2×2553114433² = 13036786615985822978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2553114395 and 2553114404.

It is not an unprimeable number, because it can be changed into a prime (2553114437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57003 + ... + 91408.

It is an arithmetic number, because the mean of its divisors is an integer number (638320012).

Almost surely, 2^2553114433 is an apocalyptic number.

It is an amenable number.

2553114433 is a deficient number, since it is larger than the sum of its proper divisors (165615).

2553114433 is a wasteful number, since it uses less digits than its factorization.

2553114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165614.

The product of its digits is 21600, while the sum is 31.

The square root of 2553114433 is about 50528.3527635723. The cubic root of 2553114433 is about 1366.7531817199.

Adding to 2553114433 its reverse (3344113552), we get a palindrome (5897227985).

The spelling of 2553114433 in words is "two billion, five hundred fifty-three million, one hundred fourteen thousand, four hundred thirty-three".