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2553114437 is a prime number
BaseRepresentation
bin1001100000101101…
…0110111101000101
320120221010122120222
42120023112331011
520212044130222
61101202034125
7120161054216
oct23013267505
96527118528
102553114437
1110a0191735
125b3048945
13318c38303
141a311940d
15ee21d542
hex982d6f45

2553114437 has 2 divisors, whose sum is σ = 2553114438. Its totient is φ = 2553114436.

The previous prime is 2553114397. The next prime is 2553114491. The reversal of 2553114437 is 7344113552.

2553114437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1289240836 + 1263873601 = 35906^2 + 35551^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553114437 - 26 = 2553114373 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2553114397 and 2553114406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2553114497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276557218 + 1276557219.

It is an arithmetic number, because the mean of its divisors is an integer number (1276557219).

Almost surely, 22553114437 is an apocalyptic number.

It is an amenable number.

2553114437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553114437 is an equidigital number, since it uses as much as digits as its factorization.

2553114437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 50400, while the sum is 35.

The square root of 2553114437 is about 50528.3528031540. The cubic root of 2553114437 is about 1366.7531824337.

Adding to 2553114437 its reverse (7344113552), we get a palindrome (9897227989).

The spelling of 2553114437 in words is "two billion, five hundred fifty-three million, one hundred fourteen thousand, four hundred thirty-seven".