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2553334041 = 3851111347
BaseRepresentation
bin1001100000110000…
…1100100100011001
320120221112210211110
42120030030210121
520212123142131
61101210450533
7120162660366
oct23014144431
96527483743
102553334041
1110a0321725
125b3133a49
13318cb425b
141a317546d
15ee263646
hex9830c919

2553334041 has 4 divisors (see below), whose sum is σ = 3404445392. Its totient is φ = 1702222692.

The previous prime is 2553334033. The next prime is 2553334051. The reversal of 2553334041 is 1404333552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2553334041 - 23 = 2553334033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2553334001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425555671 + ... + 425555676.

It is an arithmetic number, because the mean of its divisors is an integer number (851111348).

Almost surely, 22553334041 is an apocalyptic number.

It is an amenable number.

2553334041 is a deficient number, since it is larger than the sum of its proper divisors (851111351).

2553334041 is an equidigital number, since it uses as much as digits as its factorization.

2553334041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851111350.

The product of its (nonzero) digits is 21600, while the sum is 30.

The square root of 2553334041 is about 50530.5258334009. The cubic root of 2553334041 is about 1366.7923680203.

Adding to 2553334041 its reverse (1404333552), we get a palindrome (3957667593).

The spelling of 2553334041 in words is "two billion, five hundred fifty-three million, three hundred thirty-four thousand, forty-one".

Divisors: 1 3 851111347 2553334041