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255334514341 is a prime number
BaseRepresentation
bin1110110111001100011…
…1110111111010100101
3220102001200221021002111
43231303013313322211
513140411113424331
6313144332441021
724306266363464
oct3556307677245
9812050837074
10255334514341
1199317749895
124159b019171
131b10231125a
14c5030ac9db
1569962eadb1
hex3b731f7ea5

255334514341 has 2 divisors, whose sum is σ = 255334514342. Its totient is φ = 255334514340.

The previous prime is 255334514311. The next prime is 255334514353. The reversal of 255334514341 is 143415433552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207002250625 + 48332263716 = 454975^2 + 219846^2 .

It is a cyclic number.

It is not a de Polignac number, because 255334514341 - 27 = 255334514213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 255334514294 and 255334514303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255334514311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127667257170 + 127667257171.

It is an arithmetic number, because the mean of its divisors is an integer number (127667257171).

Almost surely, 2255334514341 is an apocalyptic number.

It is an amenable number.

255334514341 is a deficient number, since it is larger than the sum of its proper divisors (1).

255334514341 is an equidigital number, since it uses as much as digits as its factorization.

255334514341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432000, while the sum is 40.

Adding to 255334514341 its reverse (143415433552), we get a palindrome (398749947893).

The spelling of 255334514341 in words is "two hundred fifty-five billion, three hundred thirty-four million, five hundred fourteen thousand, three hundred forty-one".