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255342105143 = 4149409126047
BaseRepresentation
bin1110110111001110010…
…0110101001000110111
3220102002020012220201022
43231303210311020313
513140420034331033
6313145203251355
724306421040216
oct3556344651067
9812066186638
10255342105143
1199320a63984
12415a1679b5b
131b103a6b358
14c5040c707d
156996cea098
hex3b73935237

255342105143 has 8 divisors (see below), whose sum is σ = 261577330560. Its totient is φ = 249107230720.

The previous prime is 255342105119. The next prime is 255342105181. The reversal of 255342105143 is 341501243552.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 255342105143 - 28 = 255342104887 is a prime.

It is a super-4 number, since 4×2553421051434 (a number of 47 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255342101143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1962746 + ... + 2088792.

It is an arithmetic number, because the mean of its divisors is an integer number (32697166320).

Almost surely, 2255342105143 is an apocalyptic number.

255342105143 is a deficient number, since it is larger than the sum of its proper divisors (6235225417).

255342105143 is a wasteful number, since it uses less digits than its factorization.

255342105143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175497.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 255342105143 its reverse (341501243552), we get a palindrome (596843348695).

The spelling of 255342105143 in words is "two hundred fifty-five billion, three hundred forty-two million, one hundred five thousand, one hundred forty-three".

Divisors: 1 41 49409 126047 2025769 5167927 6227856223 255342105143