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255342105145 = 551068421029
BaseRepresentation
bin1110110111001110010…
…0110101001000111001
3220102002020012220201101
43231303210311020321
513140420034331040
6313145203251401
724306421040221
oct3556344651071
9812066186641
10255342105145
1199320a63986
12415a1679b61
131b103a6b35a
14c5040c7081
156996cea09a
hex3b73935239

255342105145 has 4 divisors (see below), whose sum is σ = 306410526180. Its totient is φ = 204273684112.

The previous prime is 255342105119. The next prime is 255342105181. The reversal of 255342105145 is 541501243552.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 187498526121 + 67843579024 = 433011^2 + 260468^2 .

It is a cyclic number.

It is not a de Polignac number, because 255342105145 - 213 = 255342096953 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25534210510 + ... + 25534210519.

It is an arithmetic number, because the mean of its divisors is an integer number (76602631545).

Almost surely, 2255342105145 is an apocalyptic number.

It is an amenable number.

255342105145 is a deficient number, since it is larger than the sum of its proper divisors (51068421035).

255342105145 is an equidigital number, since it uses as much as digits as its factorization.

255342105145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51068421034.

The product of its (nonzero) digits is 120000, while the sum is 37.

Adding to 255342105145 its reverse (541501243552), we get a palindrome (796843348697).

The spelling of 255342105145 in words is "two hundred fifty-five billion, three hundred forty-two million, one hundred five thousand, one hundred forty-five".

Divisors: 1 5 51068421029 255342105145