255350035 has 4 divisors (see below), whose sum is σ = 306420048. Its totient is φ = 204280024.

The previous prime is 255349999. The next prime is 255350077. The reversal of 255350035 is 530053552.

255350035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255350035 - 2⁷ = 255349907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 255349985 and 255350012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25534999 + ... + 25535008.

It is an arithmetic number, because the mean of its divisors is an integer number (76605012).

Almost surely, 2^255350035 is an apocalyptic number.

255350035 is a deficient number, since it is larger than the sum of its proper divisors (51070013).

255350035 is an equidigital number, since it uses as much as digits as its factorization.

255350035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51070012.

The product of its (nonzero) digits is 11250, while the sum is 28.

The square root of 255350035 is about 15979.6756850695. The cubic root of 255350035 is about 634.4225929010.

The spelling of 255350035 in words is "two hundred fifty-five million, three hundred fifty thousand, thirty-five".