Base | Representation |
---|---|
bin | 1110110111010111001… |
… | …0110110011000111001 |
3 | 220102011211021101002021 |
4 | 3231311302312120321 |
5 | 13141004102202323 |
6 | 313153013234441 |
7 | 24310352346226 |
oct | 3556562663071 |
9 | 812154241067 |
10 | 255379334713 |
11 | 9933aa82018 |
12 | 415b2032a21 |
13 | 1b10b6a4b99 |
14 | c50901894d |
15 | 699a20105d |
hex | 3b75cb6639 |
255379334713 has 2 divisors, whose sum is σ = 255379334714. Its totient is φ = 255379334712.
The previous prime is 255379334699. The next prime is 255379334729. The reversal of 255379334713 is 317433973552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 139896944784 + 115482389929 = 374028^2 + 339827^2 .
It is a cyclic number.
It is not a de Polignac number, because 255379334713 - 229 = 254842463801 is a prime.
It is not a weakly prime, because it can be changed into another prime (255379334813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127689667356 + 127689667357.
It is an arithmetic number, because the mean of its divisors is an integer number (127689667357).
Almost surely, 2255379334713 is an apocalyptic number.
It is an amenable number.
255379334713 is a deficient number, since it is larger than the sum of its proper divisors (1).
255379334713 is an equidigital number, since it uses as much as digits as its factorization.
255379334713 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7144200, while the sum is 52.
The spelling of 255379334713 in words is "two hundred fifty-five billion, three hundred seventy-nine million, three hundred thirty-four thousand, seven hundred thirteen".
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