Base | Representation |
---|---|
bin | 1011100111010010110101… |
… | …10011100100101100101001 |
3 | 10100102112122121222111001021 |
4 | 11303221122303210230221 |
5 | 11321414142121323423 |
6 | 130152345443252441 |
7 | 5244106054516141 |
oct | 563513263445451 |
9 | 110375577874037 |
10 | 25539399011113 |
11 | 815721aa271a9 |
12 | 2a4585907a121 |
13 | 113347cbc45a0 |
14 | 644183671921 |
15 | 2e451205b95d |
hex | 173a5ace4b29 |
25539399011113 has 16 divisors (see below), whose sum is σ = 29134549550736. Its totient is φ = 22178398279680.
The previous prime is 25539399011083. The next prime is 25539399011129. The reversal of 25539399011113 is 31111099393552.
It can be written as a sum of positive squares in 8 ways, for example, as 33697210624 + 25505701800489 = 183568^2 + 5050317^2 .
It is a cyclic number.
It is not a de Polignac number, because 25539399011113 - 25 = 25539399011081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25539399017113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24692308 + ... + 25705813.
It is an arithmetic number, because the mean of its divisors is an integer number (1820909346921).
Almost surely, 225539399011113 is an apocalyptic number.
It is an amenable number.
25539399011113 is a deficient number, since it is larger than the sum of its proper divisors (3595150539623).
25539399011113 is a wasteful number, since it uses less digits than its factorization.
25539399011113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50400444.
The product of its (nonzero) digits is 984150, while the sum is 52.
The spelling of 25539399011113 in words is "twenty-five trillion, five hundred thirty-nine billion, three hundred ninety-nine million, eleven thousand, one hundred thirteen".
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