Base | Representation |
---|---|
bin | 100101001010101110010… |
… | …001111001001010101011 |
3 | 100001011200000200002121111 |
4 | 211022232101321022223 |
5 | 313321331413000021 |
6 | 5233204142251151 |
7 | 352346556016153 |
oct | 45125621711253 |
9 | 10034600602544 |
10 | 2554134500011 |
11 | 8a5225380396 |
12 | 353012586ab7 |
13 | 156b13ba6373 |
14 | 8b899569763 |
15 | 4668b4478e1 |
hex | 252ae4792ab |
2554134500011 has 8 divisors (see below), whose sum is σ = 2710801413504. Its totient is φ = 2398181331840.
The previous prime is 2554134499991. The next prime is 2554134500017. The reversal of 2554134500011 is 1100054314552.
2554134500011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2554134500011 - 211 = 2554134497963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2554134500017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 178428955 + ... + 178443268.
It is an arithmetic number, because the mean of its divisors is an integer number (338850176688).
Almost surely, 22554134500011 is an apocalyptic number.
2554134500011 is a deficient number, since it is larger than the sum of its proper divisors (156666913493).
2554134500011 is a wasteful number, since it uses less digits than its factorization.
2554134500011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 356872661.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 2554134500011 its reverse (1100054314552), we get a palindrome (3654188814563).
The spelling of 2554134500011 in words is "two trillion, five hundred fifty-four billion, one hundred thirty-four million, five hundred thousand, eleven".
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