Base | Representation |
---|---|
bin | 10111110010011111… |
… | …111111101011100101 |
3 | 2102221011020121002111 |
4 | 113302133333223211 |
5 | 404303041410203 |
6 | 15422345441021 |
7 | 1562662360462 |
oct | 276237775345 |
9 | 72834217074 |
10 | 25543310053 |
11 | a9185949a8 |
12 | 4b4a4a0171 |
13 | 2540c73961 |
14 | 13445b4669 |
15 | 9e774326d |
hex | 5f27ffae5 |
25543310053 has 2 divisors, whose sum is σ = 25543310054. Its totient is φ = 25543310052.
The previous prime is 25543309991. The next prime is 25543310057. The reversal of 25543310053 is 35001334552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24380636449 + 1162673604 = 156143^2 + 34098^2 .
It is a cyclic number.
It is not a de Polignac number, because 25543310053 - 217 = 25543178981 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25543309997 and 25543310024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25543310057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12771655026 + 12771655027.
It is an arithmetic number, because the mean of its divisors is an integer number (12771655027).
Almost surely, 225543310053 is an apocalyptic number.
It is an amenable number.
25543310053 is a deficient number, since it is larger than the sum of its proper divisors (1).
25543310053 is an equidigital number, since it uses as much as digits as its factorization.
25543310053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 25543310053 in words is "twenty-five billion, five hundred forty-three million, three hundred ten thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.181 sec. • engine limits •