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2554641433 is a prime number
BaseRepresentation
bin1001100001000100…
…1011110000011001
320121001000020020101
42120101023300121
520212442011213
61101254455401
7120210044131
oct23021136031
96531006211
102554641433
1110a1034a13
125b3664561
13319351366
141a33d5ac1
15ee420bdd
hex9844bc19

2554641433 has 2 divisors, whose sum is σ = 2554641434. Its totient is φ = 2554641432.

The previous prime is 2554641389. The next prime is 2554641443. The reversal of 2554641433 is 3341464552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1975180249 + 579461184 = 44443^2 + 24072^2 .

It is a cyclic number.

It is not a de Polignac number, because 2554641433 - 213 = 2554633241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2554641392 and 2554641401.

It is not a weakly prime, because it can be changed into another prime (2554641443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277320716 + 1277320717.

It is an arithmetic number, because the mean of its divisors is an integer number (1277320717).

Almost surely, 22554641433 is an apocalyptic number.

It is an amenable number.

2554641433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2554641433 is an equidigital number, since it uses as much as digits as its factorization.

2554641433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 172800, while the sum is 37.

The square root of 2554641433 is about 50543.4608332275. The cubic root of 2554641433 is about 1367.0256092748.

The spelling of 2554641433 in words is "two billion, five hundred fifty-four million, six hundred forty-one thousand, four hundred thirty-three".