25548436041397 has 2 divisors, whose sum is σ = 25548436041398. Its totient is φ = 25548436041396.

The previous prime is 25548436041361. The next prime is 25548436041407. The reversal of 25548436041397 is 79314063484552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24619151609361 + 929284432036 = 4961769^2 + 963994^2 .

It is a cyclic number.

It is not a de Polignac number, because 25548436041397 - 2⁴³ = 16752343019189 is a prime.

It is a super-3 number, since 3×25548436041397³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25548436041497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12774218020698 + 12774218020699.

It is an arithmetic number, because the mean of its divisors is an integer number (12774218020699).

It is a 1-persistent number, because it is pandigital, but 2⋅25548436041397 = 51096872082794 is not.

Almost surely, 2^{25548436041397} is an apocalyptic number.

It is an amenable number.

25548436041397 is a deficient number, since it is larger than the sum of its proper divisors (1).

25548436041397 is an equidigital number, since it uses as much as digits as its factorization.

25548436041397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87091200, while the sum is 61.

The spelling of 25548436041397 in words is "twenty-five trillion, five hundred forty-eight billion, four hundred thirty-six million, forty-one thousand, three hundred ninety-seven".