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2555141311133 is a prime number
BaseRepresentation
bin100101001011101010010…
…010100100101010011101
3100001021021012011101211022
4211023222102210222131
5313330412133424013
65233452105533525
7352413532535435
oct45135222445235
910037235141738
102555141311133
118a56a17264a4
123532537a42a5
13156c446597a8
148b95316b2c5
15466e9a22008
hex252ea4a4a9d

2555141311133 has 2 divisors, whose sum is σ = 2555141311134. Its totient is φ = 2555141311132.

The previous prime is 2555141311067. The next prime is 2555141311171. The reversal of 2555141311133 is 3311131415552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2553035143684 + 2106167449 = 1597822^2 + 45893^2 .

It is a cyclic number.

It is not a de Polignac number, because 2555141311133 - 210 = 2555141310109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2555141311093 and 2555141311102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2555141311033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277570655566 + 1277570655567.

It is an arithmetic number, because the mean of its divisors is an integer number (1277570655567).

Almost surely, 22555141311133 is an apocalyptic number.

It is an amenable number.

2555141311133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2555141311133 is an equidigital number, since it uses as much as digits as its factorization.

2555141311133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27000, while the sum is 35.

Adding to 2555141311133 its reverse (3311131415552), we get a palindrome (5866272726685).

The spelling of 2555141311133 in words is "two trillion, five hundred fifty-five billion, one hundred forty-one million, three hundred eleven thousand, one hundred thirty-three".